Question

1. Solve by factorization 2x^2 + 3x = 35.​

Answer 1

Answer:

+3x=35

2x^{2}+3x=35

2x2+3x=35

Factor1

Move terms to the left side

22+3=35

2x^{2}+3x=35

2x2+3x=35

22+3−35=0

2x^{2}+3x-35=0

2x2+3x−35=0

2

Use the sum-product pattern

22+3−35=0

2x^{2}+{\color{#c92786}{3x}}-35=0

2x2+3x−35=0

22+10−7−35=0

2x^{2}+{\color{#c92786}{10x}}{\color{#c92786}{-7x}}-35=0

2x2+10x−7x−35=0

3

Common factor from the two pairs

(22+10)+l(−7x−35)=0

(2x^{2}+10x)+(-7x-35)=0

(2x2+10x)+(−7x−35)=0

2

(+5)−7(+5)=0

2x(x+5)-7(x+5)=0

2x(x+5)−7(x+5)=0

3 more steps

Solution

=7/2

=−5

Step-by-step explanation:

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