Question

1. solve by factorization method 2x2+x-6=0​

Answer 1

$\bf{{2x}^{2} + x - 6 = 0}$

$\bf{{2x}^{2} + 4x - 3x - 6 = 0}$

$\bf{2x(x + 2) - 3(x + 2) = 0}$

$\bf{(x + 2) (2x - 3) = 0}$

$\bf{Either, \ x + 2 = 0}$

$\bf{x = - 2}$

$\bf{Or, \ 2x - 3 = 0}$

$\bf{x = \dfrac{3}{2}}$

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Answer 2

Answer:

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