Question

1. Solve
by
Substitution
me thod -
8х+6y - Il = 0
3x+4y-10=0​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$8x + 6y - 11 = 0 \\ 8x = 11 - 6y \\ x = \frac{11 - 6y}{8}$

$3x + 4y - 10 = 0 \\ 3( \frac{11 - 6y}{8} ) + 4y - 10 = 0 \\ 3(11 - 6y) + 32y - 80 = 0 \\ 33 - 18y + 32y - 80 = 0 \\ 14y - 47 = 0 \\ 14y = 47 \\ y = \frac{47}{14}$

$8x = 11 - 6y \\ 8x = 11 - 6( \frac{47}{14} ) \\ 8x = 11 - \frac{141}{7} \\ 8x = \frac{77 - 141}{7} \\ 8x = \frac{ - 64}{7} \\ x = \frac{ - 8}{7}$

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