Question

1. Solve each of the following equations: (a) 3(x-1)-(x + 4) = x +5(x - 1)​

Answer 1

Answer:

$3\left(x-1\right)-\left(x+4\right)=x+5\left(x-1\right)\quad :\quad x=-\frac{1}{2}\quad \left(\mathrm{Decimal}:\quad x=-0.5\right)$

Step-by-step explanation:

$3\left(x-1\right)-\left(x+4\right)=x+5\left(x-1\right)$

$2x-7=x+5x-5$

$\mathrm{Add\:similar\:elements:}\:x+5x=6x$

$2x-7=6x-5$

$\mathrm{Add\:}7\mathrm{\:to\:both\:sides}$

$2x-7+7=6x-5+7$

$2x=6x+2$

$\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}$

$2x-6x=6x+2-6x$

$-4x=2$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4x}{-4}=\frac{2}{-4}$

$x=-\frac{1}{2}$

Answer 2

$\huge\sf\underline\red{Answer}$

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(a) 3(x-1)-(x + 4) = x +5(x - 1)

$\: 3(x - 1) -( x + 4) = x+ 5(x - 1) \\ \\ \\ 3x - 3 - x - 4 = x + 5x - 5 \\ \\ 3x - 5x - x - x = - 5 + 3 + 4 \\ \\ 3x - x - 6 = - 5 + 7 \\ \\ 3x - 7x = 2 \\ \\ - 4x = 2 \\ \\ x = \frac{2}{ - 4} \\ \\ = - \frac{1}{2}$

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HOPE ITS HELPFUL!!