Question

1. Solve for x and y
1/ 2[2x+3y] + 12/7[3x-2y] = ½ ,
7/ [2x+3y] + 4/[3x-2y] = 2
for 2x + 3y = 0 and 3x – 2y= 0

Answer 1

Given 2x+3y=0 and 3x-2y = 0

So,
1/2 × 0 + 12/7 × 0 = 1/2
=> 0 = 1/2 ........(i)

7/0 + 4/0 = 2
=> 0 = 2 .......(ii)

Ultimately,
x = 1/2
y = 2