Question

1. Solve the equation 6x²-x-2=0 by factorization.​

Answer 1

Answer:

$6 {x}^{2} - x - 2 = 0$

$6 {x}^{2} - 4x + 3x - 2 = 0$

$2x(3x - 2) + 1(3x - 2) = 0$

$(2x + 1)(3x - 2) = 0$

Therefore,

$x = \frac{ - 1}{2} or \: x = \frac{2}{3}$

Answer 2

6x2-x-2=0
6x2-4x+3x-2=0
2x(3x-2) +1(3x-2)=0
(2x+1)(3x-2)=0
x=-1/2
or x=2/3
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