Question

1 solve the equation, sin2A = 1/2 ,THEN A= i. 15 ii. 30 iii. 45 iv. 60 2 If Sin(A+B)= 1, and Cos(A-B)=1/2 ,(I)VALUE OF A+B * i. 30 ii. 45 iii. 90 2(b)Find the value A-B i. 30 ii. 45 iii. 60 2(c) VALUES OF A and B , i. 45 ,45 ii. 65,25 iii. 75,15 3. Find the distance AB^2 ,If Aand B are(a,0 ) ,(0,b) i. a + b ii. a^2+ b^2 iii. a-b 4. if the points A(4,3) and B(X,5) are end of diameter of the circle with centre O(2,4).which formula is used i. distance formula ii. section formula iii.midpoint formula 4(ii.),find the value of x i. 0 ii. 1 iii. 2 5.Choose the correct option for, 2Tan^2A-2Sec^2A i. 2 ii. -2 iii. 0 iv. -1 6. given tanA= 4/3 .If angle B=90 .Value of CotA i. 3/5 ii. 4/5 iii. 3/4 6(ii) The value of ,cosA and cosC i. 3/5, 4/5 ii. 4/5, 3/5 iii. 3/4, 4/3 7. If the two vertices of an equilateral triangle OAB are (0,0) ,(2a,0), Then find The co-ordinates of B. if BL is median. 8. In triangleABC, angleB=90 ,If tanA=1, THEN Verify that 2SinACosA=1 9. If sinA=CosA ,then find the value of cosecA and secA . 10. What is the value of sin^2( 63) + cos^2 (63) i. 0 ii. 1 iii. 2 11.The 3 vertices of parallelogram are (3,4) (3,8) and (9,8) ,find the fourth vertex.(i)what is the coordinates of point of intersection of diagonals. *l i. (6, 6) ii. 3,6 iii. 6,3 11(ii) what f0rmula is used distance section midpoint 11(iii) fourth vertex is * i. 4,9 ii. 9 ,4 iii. 8, 5 iv. 5, 8 12. if A and B are (-2, -2),(2, -4) , find the coordinates of P such that AP/AB =3/7 and P lies on line AB. WHICH FORMULA IS USED i. Distance ii. section iii. midpoint 12(ii) find the ratio of line AB divides by P . i. 3 :7 ii. 7 : 3 iii. 3 : 4 iv. 4: 3 12(III) P0INT P is * -2/7 ,-20/7 2/7 ,20/7 3/10, 4/10 13, sinA/(1-cosA) + sinA/(1 +cosA) = 2 cosecA * 13(ii) what identity is used * i. first ii. second iii. third 13(iii) what is the LCM of denominator * 14. Find a point on x-axis which is equidistant from A(2,-5) ,B(-2 ,9). ( i)a point lie on x-axis is in form of * i. (x,y) ii. (0,x) iii. (x ,0) 14.(ii) find the coordinates of a point on x-axis *​

Answer 1

Answer:

sin2A = 1/2

or, sin2A = sin30°(value of sin30° is 1/2)

or, 2A = 30°

or, A = 15°

sin(A+B) = 1

or, sin(A+B) = sin90°

or, A + B = 90° or, A = 90°-B ----------- i)

cos(A-B) = 1/2

or, cos(A-B) = cos60°

or, (A-B) = 60°

Putting value of A from i)

90°-B - B = 60°

or, 2B = 30°

or, B = 15 °

So A = 75°