Question

1) Solve the equations 11x + 6y=4330; 22x + 5y = 7330 and
find the value of x+y.​

Answer 1

Answer:

x+y=480

Step-by-step explanation:

Given : Equations $11x+6y=4330$ and $22x+5y=7330$

To find : Solve the equation and find the value of x+y?

Solution :

$11x+6y=4330$ ......(1)

$22x+5y=7330$ ......(2)

Eliminate x by multiplying (1) by 2,

$22x+12y=8660$ ....(3)

Subtract (2) and (3),

$22x+12y-(22x+5y)=8660-7330$

$7y=1330$

$y=\frac{1330}{7}$

$y=190$

Substitute in (1),

$11x+6(190)=4330$

$11x+1140=4330$

$11x=4330-1140$

$11x=3190$

$x=\frac{3190}{11}$

$x=290$

The value of x=290 and y=190.

Now, $x+y=290+190=480$

Answer 2

Here's your answer...

Hope it helps...

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