Question

1. Solve the following:

(1) The radius of a circle is 5 cm. The distance of a chord from the centre is 4 cm. Find the length of the chord,
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Answer 1

Answer:

6cm

Step-by-step explanation:

the chord of a circle (PQ)=?

distance of the chord from the centre(OR)=4cm

radius of the circle(OP)=5cm

By Pythagoras theorem,

OPsq.=OR sq.+PR sq.

5sq.=4 sq.+PR sq.

25 =16 +PR. sq.

PR sq.=25-16

PR sq. =9cm

therefore PR=3cm

PR +QR=3+3= 6cm(the perpendicular drawn from centre to chord bisects the chord.

therefore length of the chord is 6 cm

Answer 2

Answer:

The is is bisected (because of perpendicular line from center)

by pythagoras theroem,

${5}^{2} = {4}^{2} + {x}^{2} \\ 25 - 16 = {x}^{2} \\ \sqrt{9} = x \\ x = 3cm$

So lenght of chord =2×3=6 cm

Hope it helps you...

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