Question

1. Solve the following.
(2x5=10
2
1. Find the length of a room whose area 4
sq. m and whose breadth is 3
m.
IS​

Answer 1

Answer

Here, Length of Rectangular Park =l

Breadth of Rectangular Park =l−3

Altitude of Triangular Park =12

Breadth of Triangular Park =l−3

Now,  

A  

Rectangle

​

=l(l−3)

A  

Triangle

​

=  

2

1

​

×12(l−3)

A  

Rectangle

​

−A  

Triangle

​

=4

⇒l(l−3)−  

2

1

​

×12(l−3)=4

⇒l  

2

−9l+14=0

⇒(l−2)(l−7)=0⇒l=2,7

Since, breadth is l−3 , l



=2  

∴l=7 m  and  breadth =7−3=4 m

Answer 2

Answer:

Area =4 sq.m

breadth = 3 m

length= ?

Area = l×b

4=I × 3

I = 4/3

=1.34 m

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