Math, asked by Ashikaku, 5 months ago

1) solve the following equation
a. 5t + 28 = 10
b. a /5 + 3 = 2
c. q/4 + 7 = 5
d. 5/2 x = 25/4
e.6z + 10 = - 2
f. 3 (n - 5)=21
g. 3 (n - 5)= - 21
h. 4 (2 - x) =8



Ashikaku: please answer the questions please

Answers

Answered by rukshanakhatoon21k
0

Answer:

a) 5t +28=10

5t=10-28

5t=-18

t=-18/5

t=-3.6

Answered by ananthamananth682
2

Answer:

a.5t=10-28

5t=-18

t=-3.6

b.a/5+3=2

a+15=10

a=-5

c.q/4+7=5

q+28=20

q=-8

d.5/2x=25/4

x=25/4×2/5

x=5/2

e.6z=-2-10

z=-12/6

z=-2

f.3(n-5)=21

3n-15=21

3n=21+15

3n=36

n=36/3

n=12

g.n=-12

h.4(2-x)=8

8-4x=8

-4x=8-8

x=0/4

x=0

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