1) solve the following equations. 1)4p=12
2)
\frac{t}{3} = 6
3
t =6
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4p=12
p=3
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Solution 3:
(a) 4 = 5(p-2)
4 = 5p-10
4+10 = 5p
14 = 5p
\frac{14}{5\ }=\ p\
(b) -4= 5 (p-2)
-4 = 5p -10
-4+10 = 5p
6 = 5p
\frac{6}{5\ }=\ p\
(c) 16 = 4+3 (t+2)
16 = 4+ 3t +6
16 = 10 +3t
16-10 = 3t
6 = 3t
\frac{6}{3\ }=\ t\
t = 2
(d) 4+ 5(p-1) = 34
4+ 5p -5 = 34
5p -1 = 34
5p = 35
p\ =\ \frac{35}{5}
p = 7
(e) 0 = 16 +4 (m-6 )
16 = 4(m-6 )
16 = 4m - 24
16+24 = 4m
40 = 4m
\frac{40}{4}=\ m\
10 = m
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