Question

1. Solve the following equations : ( a ) 2y + 5 = 32 (b) 5t + 28 = 10 (c) + 3 = 2 (d) + 7 = 5 (e) x = -10 (f) x = 2 (g) 7m + 19 = 13 (h) 62 + 10 = -2 (i) 31 (j) -5 = 3 2







by method ​

Answer 1

Answer:

1. 2×14+5=3
2. -1+3=2
3. -2+7=5

Answer 2

Answer:

(a) 2y + (5/2) = (37/2)

= 2y = (37/2) – (5/2)

= 2y = (37-5)/2

= 2y = 32/2

= y = 16/2 = 8

(b) 5t+28= 10

= 5t = 10 -28

= t= -18/5

(c) a/5+3 =2

= a/5= 2-3

= a=-1×5=-5

(d) q/4+7 = 5

= q/4=5-7

=a= -2 ×4= -8

(e) (5/2)x = -5

= 5x=-5×2

= x= -10/5=-2

(f) 5x/2=25

= 5x = 25×2

= x = 50/5 =10

(g) 7m+19/2 =13

= 7m = 13 -19/2 = 7m = (26-19)/2

= 7m= 7/2

= m = 7/2×1/7 =1/2

(h) 6z + 10 = -2

= 6z = -2 -10

= z = -12/ 6 = -2

(i) (3/2)I = 2/3

= I = 2/3 × 2/3 =4/9

(j) (2b/3 ) - 5 = 3

= 2b/3 = 3+5

= 2b/3 = 8

= b = (8×3)/2 = 12