Math, asked by ranjaykumar2049, 8 months ago

1.
Solve the following equations by the trial and error
method:
(i) 4y-2 =18​

Answers

Answered by deepikakadtan15
8

Answer:

y=24

Step-by-step explanation:

4y-2 =18

4y= 18+2

= 20+4=24

y= 24

please mark current answer

Answered by reshmasree95
5

hey mate good afternoon,

here is your answer

Trail and error method :-

if y = 1

4y -2 = 18

4(1) -2 = 18

4 -2 = 18

2 is not equal to 18

LHS is not equal to RHS.

if y = 2

4y -2 = 18

4(2)-2 = 18

8 -2 = 18

6 is not equal to 18

LHS is not equal to RHS.

if y = 3

4y -2 = 18

4 (3) -2 = 18

12 - 2 = 18

10 is not equal to 18

LHS is not equal to RHS.

if y = 4

4y -2 = 18

4(4) -2 = 18

16 -2 = 18

14 is not equal to 18

LHS is not equal to RHS.

if y = 5

4y -2 = 18

4 (5) -2 = 18

20 -2 = 18

18 = 18

LHS = RHS

:. y = 5

hope it helps....

please mark me as brainlist answer

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