Question

1. Solve the following equations by trial and error method:
(1) 3x + 4 = 10

(2) 19 = 11 + 2x



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Answer 1

Answer:

$3x + 4 = 10 \\ 3x = 10 - 4 \\ 3x = 6 \\ x = 2$

$19 = 11 + 2x \\ 19 - 11 = 2x \\ 8 = 2x \\ 4 = x$

Answer 2

Answer:

1) 3x+4=10

substitute x=1

=>3(1)+4=10

=>3+4=10

=>7=10

LHS IS NOT EQUAL TO RHS

so x is not equal to 1

substitute x=2

=>3(2)+4=10

=>6+4=10

10=10

LHS IS EQUAL TO RHS

so x is equal to 2

x=2

2)19=11+2x

substitute x=1

19=11+2(1)

19=11+2

19=13

LHS IS NOT EQUAL TO RHS

so x is not equal to 1

substitute x=2

19=11+2(2)

19=11+4

19=15

LHS IS NOT EQUAL TO RHS

so x is not equal to 2

substitute x=3

19=11+2(3)

19=11+6

19=17

LHS IS NOT EQUAL TO RHS

so x is not equal to 3

substitute x=4

19=11+2(4)

19=11+8

19=19

LHS IS EQUAL TO RHS

so x is equal to 4

x=4

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