Question

1.Solve the following equations
i) 6x^2 - 13x + 6 = 0.
ii) x^2 - 35x + 300= 0.
iii) x^2 - 5x - 24 = 0.
iv) 2x^2 - 3x - 35 = 0.
v) x^2 + 2ax + (a^2 - b^2) = 0.
vi) 5x^2 + 9x - 28 = 0.
vii) x^2 - 2ax + (a^2 - b^2) = 0.
viii) x^2 - 2ax + (a^2-b^2) = 0.
ix) 44x^2 + 65x + 24 = 0.​

Answer 1

Step-by-step explanation:

(i) 6x² - 13x + 6 = 0

=>6x²- 9x-4x+6=0.

=>3x(2x-3)-2(2x-3) =0 [middle term expansion]

=>(2x-3)(3x-2)=0.

=>2x-3=0 Or 3x-2=0

=>x= 3/2. Or x= 2/3

(ii) x² - 35x + 300= 0.

=>x²-15x-20x+300=0

=>x(x-15)-20(x-15)

=>(x-15)(x-20)=0

=>x-15=0 Or x-20 = 0

=>x= 15. Or x= 20

(iii) x² - 5x - 24 = 0

=>x²-8x+3x-24=0

=>x(x-8)+3(x-8)=0

=>x-8 =0. Or x+3= 0

=>x= 8 Or x =-3

(iv) 2x^2 - 3x - 35 = 0

=>2x²-10x+7x-35=0

=>2x(x-5)+7(x-5)=0

=>x-5=0 Or 2x+7=0

=>x=5 Or 2x = -7

x= -7/2

(v) x² + 2ax + (a²- b²) = 0

Here a= 1,b=2a ,c= (a²-b²)

Formula x = -b±√(b²-4ac)

2a.

Here b²-4ac = Discriminant (D)

:. x = -2a±√(4a²-4.1.(a²-b²)

2.1

= -2a±√(4a²-4(a²-b²)

2

= -a± √(-b²)

x = -a+√(-b²). Or. x= -a-√(-b²)

Other are try by using this formula............

Answer 2

Answer:

b" (and any subsequent words) was ignored because we limit queries to 32 words.plzzzz mark me as a brainilist plzz thank my answers plzzzzz