Math, asked by luvkookie18, 5 hours ago

1.solve the following linear equations in one variable:

➡(x-2)(x-3)+2(x-1)(x-3)=3(x-)(x-2)

don't spam,answer step-by-step explanation... ​

Answers

Answered by Itzeuphoria
20

linear equation in one variable

Step-by-step explanation:

(x+2)(x+3)+(x-3)(x-2)-2x(x+1)=0

→ X

2

+2x+3x+6+x

2

-3x-2x+6-2x

2

-2x=0

→ 2x

2

-2x

2

+5x-5x-2x+12=0

⇒-2x+12=0

⇒-2x=-12

⇒x=6

this \: is \: your \: answer

Answered by varshayadavalli20
5

answer

linear equation in one variable

Step-by-step explanation:

(x+2)(x+3)+(x-3)(x-2)-2x(x+1)=0

→ X

2

+2x+3x+6+x

2

-3x-2x+6-2x

2

-2x=0

2x

2

-2x

2

+5x-5x-2x+12=0

⇒-2x+12=0

>-2x=-12

⇒x=6

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