Question

1) solve the following number problems i) two parts of a number are such that one is half the other the sum of the two parts is 8 more than their difference what are the parts and what is the number? step by step explanation​

Answer 1

Answer:

one is half the other => x=y/2 the sum of the two parts = 8 more than their difference

ie x+y = 8 + (x - y)

on solving the equation

x+y -x +y = 8

2y = 8 => y = 4 so, x = 4/2 = 2

so, 2 numbers are 2 & 4

Check the solution

I condition => x = y/2

2=4/2

Il condition

x+y = 8 + (x-y)

2+4 = 8 +(4-2)

6= 8+2

ie 6(sum of the 2 no.) 8+ (more than the difference)