Question

1. Solve the following pair of linear equations by the substitution method.
(v) √2*x + √3*y =0
√3*x - √8*y =0
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Answer 1

Step-by-step explanation:

√/2x+√3y=0_________(I)

√3x-√8y=0__________(ii)

from eq (I) we get

X=-√3y/√2

by putting the value of x we get

√3(-√3y/√2)-√8y=0

-3y/√2-√8y=0

-3y-√16/√2=0

-3y-4y=0

-7y=0

y=-1/7

by putting the value of y in (I) we get

√2x+√3x-1/7=0

√2x-√3/7=0

7√2x-√3/7=0

7√2x-√3=0

7√2x=√3

X=√3/7√2

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