Question

1. solve this problem ​

Answer 1

Answer:

$\cos(0) \times \sin( \frac{\pi}{2} ) \times { \cos( \frac{\pi}{6} ) }^{2} \times { \sec( \frac{\pi}{4} ) }^{2}$

We know that,

$\cos(0) = 1 \\ \sin( \frac{\pi}{2} ) = 1 \\ \cos( \frac{\pi}{6} ) = \frac{ \sqrt{3} }{2} \\ \sec( \frac{\pi}{4} ) = \sqrt{2}$

Hence we get,

$1 \times 1 \times { \binom{ \sqrt{3} }{2} }^{2} \times { ( \sqrt{2}) }^{2}$

$\frac{3}{4} \times 2$

$= \frac{3}{2}$

This is what we need.

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