Question

1) Solve.
use²-v4x2-2x-6=0 by using
shridora charya fromuta​

Answer 1

Answer:

Here,

a = 4 ,

b = - 2 ,

c = - 6

Using Shridhara Charya formula -

$=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\\=\dfrac{-(-2)\pm\sqrt{(-2)^2-4(4)(-6)}}{2(4)}\\\\\\=\dfrac{2\pm\sqrt{4+96}}{8}\\\\\\=\dfrac{2\pm10}}{8}\\\\\\=\dfrac{3}{2} or - 1$

Required values are 3/2 and - 1.

Answer 2

Answer :

Given : $\tt{\sqrt{4{x}^{2}-2x-6}}$

Here,

• a = 4
• b = -2
• c = -6

We know that, Shree Dhara charya formula : $\tt{\dfrac{-b\pm\sqrt{{b}^{2}-4ac}}{2a}}$

Using this formula to find the value of x.

$\sf{=\dfrac{-(-2)\pm\sqrt{{(-2)}^{2}-4\times 4 \times (-6)}}{2\times 4}}$

$\sf{=\dfrac{2\pm\sqrt{4-(-96)}}{8}}$

$\sf{=\dfrac{2\pm\sqrt{4+96}}{8}}$

$\sf{=\dfrac{2\pm\sqrt{100}}{8}}$

$\sf{=\dfrac{2+\sqrt{100}}{8}\:OR\:\dfrac{2-\sqrt{100}}{8}}$

$\sf{=\dfrac{2+10}{8}\:OR\:\dfrac{2-10}{8}}$

$\sf{=\dfrac{12}{8}\:OR\:\dfrac{(-8)}{8}}$

$\bf\underline{=\dfrac{3}{2}\:OR\:(-1)}$

Hence, Roots = 3/2 and -1.