Question

(1) Solve using determinants :
(a) 2x + 3y + 1 = 0
3x - 2y - 5 = 0​

Answer 1

OK i understand your question

First we eqⁿ in correct

2x + 3y = -1

3x - 2y = 5

Finding D

| 2 3 |

D = | 3 -2 |

= 2 × -2 - 3 × 3

= -4 - 9

= -13

D = -13

| -1 3 |

Dx = | 5 -2 |

= ( -1 × -2 ) - ( 5 × 3 )

= 2 - 15

= -13

Dx = -13

| 2 -1 |

By = | 3 5 |

= 2 × 5 - 3 × -1

= 10 - ( -3)

= 10 + 3

= 13

Dy = 13

Find x

$x \: = \frac{Dx}{D} \\ x = \frac{ - 13}{ - 13} \\ x = 1$

x = 1

Finding y

$y = \frac{Dy}{D} \\ y = \frac{13}{ - 13} \\ y = - 1$

y = -1