Question

1.Solvei)y–8=20 ii)6x+6=66

2.Whatshouldbeaddedto2x+8ytoget6x–10y.​

Answer 1

Answer:

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Step-by-step explanation:

1) i) y-8 =20= y=20+8=28

ii) 6x+6=66 =6x=66-6 =6x=60

=x=60/6=10

2) let that number be z that should be added

so our equation will be=

2x+8y+z=6y-10y

so our next step towards,

z=6x-10y-2x-8y

z=4x-18y

so it's our answer

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Answer 2

Answer:

1) i) y - 8 = 20

= y = 20 + 8

= y = 28.

ii) 6x + 6 = 66

= 6x = 66-6

= x = 60/6

= x = 10.

2) let the no. be l, then

ATP,

l + (2x + 8y) = 6x - 10y

= l = (6x - 10y) - (2x + 8y)

= l = 6x - 10y - 2x - 8y

= l = 6x - 2x - 10y - 8y

= l = 4x - 18y.

therefore, 4x - 18 y should  be added to 2x + 8y to get 6x - 10y.

Step-by-step explanation: