Question

1) Some measures are given in the adjacent figure,
find the area of ABCD.
B
40 m
A
13 m
9 m
C С
D
T
60 m​

Answer 1

Answer:

Area of ABCD = ar(ΔABD)+ar(BCD)

area of triangle =

2

1

(base)(height)

→arc(ABCD)=

2

1

(AB)(AD)+

2

1

(BT)(CD)

=

2

1

(360+780)=

2

1

×1140=570m

2

Step-by-step explanation:

hope this helps

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