Question

1. Sphere of diameter 26.4 cm is half-filled with acid. The acid is drained into a cylindrical beaker of diameter 16cm. Find the depth of the acid in the beaker.

Answer 1

Answer:

Squere radius: 13.2cm

Volume of Sphere: $\frac{4}{3} \pi r^2$

Volume of Sphere (S):

S =  $\frac{4}{3} \pi 13.2^2$

S = $\frac{4}{3} \pi 174.24^2$

S= $\frac{696.96}{3} \pi$

S=729.85 cm²

The quantity of acid in sphere is equal to half-volume of the sphere: 364.92 cm².

Volume of a Cylinder(B): $\pi r^{2} h$

Beaker volume is equal to half-volume of the square.

364.92 = $\pi r^{2} h$

364.92 = $\pi 16^{2} h$

Once we want to know the liquid height:

$h=\frac{364.92}{256\pi }$

$h=\frac{364.92}{804.24 }$

$h=0.4527 cm$

∴The depth of the acid in the beaker is 0.4527 cm

Answer 2

Answer:

Step-by-step explanation:

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