1. State the meaning of recoil velocity of a gun.
2. Mass of a body is doubled. How does its acceleration change under a given force?
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1.Recoil velocity is the speed with which the rifle or pistol recoils when the bullet is fired. ... Since the gun is many times heavier than a bullet, the recoil acceleration (and peak velocity) is many times less than the bullet (and powder) acceleration (and peak velocity).
2.We know,
F = ma
=> a = F/m
So, when mass is doubled keeping the force constant,
a = F/(2m) = a/2
Acceleration becomes half.
2.We know,
F = ma
=> a = F/m
So, when mass is doubled keeping the force constant,
a = F/(2m) = a/2
Acceleration becomes half.
vedantranade:
thanks
Answered by
1
Answer:
New acceleration will be half of original acceleration
Given-
Mass of a body is doubled
To Find-
How does its acceleration change under given force
Formula Applied-
F=ma
Solution-
Force for a body of mass , m with acceleration a is given by ,
F = ma
a = F/m....(1)
When mass of a body is doubled , we need to find how acceleration changes under given force ,
⇒ m' = 2m
⇒ a' = ?
⇒ F' = F
Since , same force acting
Apply formula ,
F = ma
F' = m'a'
(F) =(2m)a'
F = 2a'm
a' = 1/2(F/m)
a' = 1/2(a) [from (1)]
a' = a/2
So , new acceleration will be half of original acceleration
Explanation:
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