Question

1.Stephen has been working on programing and updating a Web site for his company for the past 15 months. The following numbers represent the number of hours Stephen has worked on this Web site for each of the past 7 months:

24, 25, 31, 50, 50, 66, 78

A) What is the mean (average) number of hours that Stephen worked on this Web site each month? 3M

B) Find the median. 1M
C)Find the mode. 1M ​

Answer 1

Answer:

MEAN=46.28

MEDIAN=50

MODE=78

Step-by-step explanation:

MEAN=

$\frac{sum \: of \: frequencies}{total \: number \: of \: frequencies}$

=324/7=46.28

MEDIAN=Arrange the given number in ascending number and select the middle one or if the number of given frequencies is even just divide it by 2 and select that number from the series. And if it is odd ,add 1 and divide it by 2

MODE=Highest value in the given frequencies

Answer 2

Answer:

A) 47

B) 50

C) 50

Step-by-step explanation:

A) The sum of the hours Steven worked ---

= 24+25+31+50+50+66+78

= 329

Therefore, mean hours = sum of total hours/total number of days worked

= 329/7

= 47

B) In ascending order - 24,25,31,50,50,66,78

Total number of observations = n = 7, which is odd

Median = n + 1/2 th of observation

= 7 + 1/2 th of observation

= 4th of observation

= 50

C) Most common number among the observations --

24,25,31,50,50,66,78

Therefore, mode is 50.

Hope it helps.

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Thank you.