Question

1.
stions (one mark each)
How many gms of bromine will react with 28 gm of C3H6?
a) 80
b) 160
c) 240
d) 320​

Answer 1

Explanation:

42 grams

1 mole

Propane

CH

3

−CH=CH

2

+

160 gms

1 mole

Br

2

→CH

3

−

1,2-dibromo propane

Br

∣

CH

2

−

Br

∣

CH

2

∵42gms of propane reacts with 160gms of bromine.

∴21gms of propane

42

160

×21=80gms.

I hope it will help you