Math, asked by sreekarreddy91, 6 days ago

1. Subtract :- 3xy²z from -12xy²z.

2. Find the product of 2x, 3x²y and -5xy²z².

3. Add :- 3xy - 4yz + 2zx ; 3yz + 6zx - 5y and 5y - 2yz + 3zx

4. Subtract :- 2pq ( p + q ) from 3pq ( p - q )

5. Multiply :- ( a² + b² ) and ( 5b - 3a )​

Answers

Answered by crazybot007
22

1{ \bold{.3x {y}^{2}z - 12x {y}^{2}z =  - 9x {y}^{2} z  }}  \\ 2{ \bold{.2x  \times 3 {x}^{2}y \times  - 5x {y}^{2}  {z}^{2} =  - 30 {x}^{3} y^{3}   {z}^{2}  }} \\ 3.{ \bold{6 {y}^{3}xz - 11yz + 11zx }} \\ 4.{ \bold{ - 1pq}} \\ 5.{ \bold{yi}}

Answered by amansharma264
51

EXPLANATION.

(1) Subtract :

⇒ - 3xy²z from - 12xy²z.

As we know that,

We can write equation as,

⇒ - 12xy²z - (- 3xy²z).

⇒ - 12xy²z + 3xy²z.

- 9xy²z.

(2) Find the products :

⇒ (2x), (3x²y) and (- 5xy²z²).

As we know that,

We can write equation as,

⇒ (2x)(3x²y)(- 5xy²z²).

- 30x⁴y³z².

(3) Add :

3xy - 4yz + 2zx  and  3yz + 6zx - 5y  and  5y - 2yz + 3zx.

As we know that,

We can write equation as,

⇒ (3xy - 4yz + 2zx) + (3yz + 6zx - 5y).

⇒ 3xy - 4yz + 2zx + 3yz + 6zx - 5y.

⇒ 3xy - yz + 8zx - 5y.

⇒ (3xy - yz + 8zx - 5y) + (5y - 2yz + 3zx).

⇒ 3xy - yz + 8zx - 5y + 5y - 2yz + 3zx.

3xy - 3yz + 11zx.

(4) Subtract :

2pq(p + q)  from  3pq(p - q).

As we know that,

We can write equation as,

⇒ 2p²q + 2pq²  from  3p²q - 3pq².

⇒ (3p²q - 3pq²) - (2p²q + 2pq²).

⇒ 3p²q - 3pq² - 2p²q - 2pq².

⇒ p²q - 5pq².

pq(p - 5q).

(5) Multiply :

⇒ (a² + b²)  and (5b - 3a).

As we know that,

We can write equation as,

⇒ (a² + b²) x (5b - 3a).

⇒ a²(5b - 3a) + b²(5b - 3a).

5a²b - 3a³ + 5b³ - 3ab².

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