Question

1.. Subtract : (i) 3 from –4 (ii) –3 from –42.The sum of two integers is 47. If one of the integers is – 24,

find the other.

3.Find 3/4 of (i) 16 (ii) 36

4.Find the area of rectangle whose length is 5.7cm and breadth is 3 cm.

5.Express 0.041 as a fraction.

6.Find the average of 4.2, 3.8 and 7.6.

7.Find the mean of first six multiples of 5.

8.. Find the mode of 2, 6, 5, 3, 0, 3, 4, 3, 2, 4, 5, 2, 4.

9.Write equations for the following statements:

(i) The sum of numbers x and 4 is 9. (ii) The difference between y and 2 is 8.(iii) Ten times a is 70. (iv) The

number b divided by 5 gives 6

10.Solve: (a) 3n + 7 = 25 (b) 2p – 1 = 23 (c) 12p – 5 = 25

11.. The three angles of a triangle are in the ratio 1:2:1. Find all the angles of the triangle.

12.72% of 25 students are good in hindi, how many are not good in hindi.

13.Subtract 24ab – 10b – 18a from 30ab + 12b + 14a.

14.Express:(i) 729 as a power of 3. (ii) 128 as a power of 2(iii) 343 as a power of 7. (iv) 256 as a

power 2.15..Write the following numbers in standard form.(i) 0.000000564 (ii) 0.000002 (iii)

21600000


anyone who can answer the whole question​

Answer 1

Step-by-step explanation:

1.i) -4 -3 =-7

ii) -42 - 3 =-45

2.let x be the other integer

x+ (-24) =-47

x= -47 + 24 (by transposing)

x = -23

3. 3/4 of 16 =12

3/4 of 36 =27

4.area =l*b

l =5.7cm

b=3cm

area =5.7 *3

17.1 cm squared

5.41/100

6. 3.8 +7.6 + 4.2=15.6

15.6 /3=5.2

I will send the rest later

Answer 2

(13)

30ab+12b+14a-(24ab-10b-18a)

= 30ab+12b+14a -24ab + 10b +18 a

= 6ab +22b+32a

14)

make factors

729 as a power of 3

729 = 9×9×9 = 3×3×3×3×3×3

729 = 3^6

ii)128.as a power of 2

128.= 4×4×4×2

= 2²×2²×2²×2

128 = 2^7

iii)343 as a powee of 7

343 = 7×7×7

= 7³