Question

1
subtract the sum of -2–– and
5
-14/21 from the sum of 3/5 and
21/9.​

Answer 1

Step-by-step explanation:

$( \frac{3}{5} + \frac{21}{9} ) - ( - 2 \frac{1}{5} + \frac{ - 14}{21} ) \\ = ( \frac{3}{5} + \frac{ \cancel{ 21}_{ \: \: 7}}{ \cancel 9_{ \: \: 3} } ) - ( \frac{ - 11}{5} + \frac{ \cancel{ - 14} _{ \: \: - 2}}{ \cancel{ 21} _{ \: \: 3} } ) \\ = ( \frac{3}{5} + \frac{7}{3} ) - ( \frac{ - 11}{5} + \frac{ - 2}{3} ) \\ = ( \frac{9 + 35}{15} ) - ( \frac{ - 33 + ( - 10)}{15} ) \\ = \frac{44}{15} - ( \frac{ - 33 - 10}{15} ) \\ = \frac{44}{15} - \frac{ - 43}{15} \\ = \frac{44 - ( - 43)}{15} \\ = \frac{44 + 43}{15} \\ = \frac{ \cancel{ 87} _{ \: \: 29} }{ \cancel{15} _{ \: \: 5}} \\ = \frac{29}{5} \\ \boxed{ = \underline{ \underline{\large 5 \frac{4}{5} }}}$