Question

1. Suhaas borrowed a certain amount at 28% p.a.
compound interest and repays it in one year. Bhanu
borrows a certain amount at a certain interest rate
under simple interest and returns it after four years. If
the amounts repaid by Suhaas and Bhanu are the
same and that is equal to 38400 and the sum of their
principals borrowed is 54000, at what rate Bhanu
paid the interest?
(A) 10 % pa
(B) 12% p.a
(C) 15% p.a
(D) 18% p.a​

Answer 1

Step-by-step explanation:

(B) 12% p.

Bhanu

borrows a certain amount at a certain interest rate

under simple interest and returns it after four years. If

the

Answer 2

Answer:

Bhanu paid 15% rate of interest.

So, option (c) is the correct answer.

Step-by-step explanation:

Given,Suhaas borrowed a certain amount at 28% p.a. compound interest and repays it in one year and he repay 38400 rupees.

We know,

Total amount = $p {(1 + \frac{r}{100}) }^{t}$

Where p is principal,r is rate of interest and t is time.

Here,

$r = 28\% \\ t = 1$

and total amount = 38400 rupees.

So,

$38400 = p {(1 + \frac{28}{100}) }^{1} \\ p \times \frac{128}{100} = 38400 \\ p = 38400 \times \frac{100}{128} \\ p = 300 \times 100 \\ p = 30000$

Therefore Suhaas borrowed 30000 rupees.

It is given that Suhaas and Bhanu borrowed total 54000 rupees.

So,Bhanu borrowed

$= (54000 - 30000) = 24000 \: rupees$

and it is also given Bhanu borrowed his money for 4 years.

So,in the case of Bhanu principal is 24000 rupees and time is 4 years and the amounts repaid by Suhaas and Bhanu are the same and that is equal to 38400

Now,we want to find value of rate of interest.

Let required rate of interest be x%

Now by simple interest rule,

Amount $= p + \frac{prt}{100}$

Here,

$24000 + \frac{24000 \times 4 \times x}{100} = 38400 \\ (240\times 4 \times x) = 38400 - 24000 \\ (240 \times 4 \times x) = 14400 \\ x = \frac{14400}{240 \times 4} \\ x = 15$

Therefore required rate of interest is 15%.

Know more about Compound interest,

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