Question

1. Sum of first n natural number is
n(n+1)
(a) n(n-1)/2
(b)n(n+1)/2
(c) n(n+1)(2n + 1)/6
(d) [n(n+1)/2]^2​

Answer 1

Answer:

b n(n+1)/2is ur ans

Step-by-step explanation:

n(n+1)

1(1n+1)

2n+1

n=2/1