Question

1. Sum of the areas of two squares is 468 m. If the difference of their perimeters is 24 m,
find the sides of the two squares.​

Answer 1

Answer:

the different of a perimeters is 24 m A/q therefore 4x_4y =24 therefore perimetrs of squares =4× 24

4× sides of square 2= 4×_ 24

side of square 2= 4x_24 =4(x_6) = x_6

4. 4