Math, asked by krishnakant432828, 8 months ago

1) Sum of the digits of a two-digit number is 9. When we interchange the digits, it is
found that the resulting new number is greater than the original number by 27. What
is the two-digit number?

Answers

Answered by jtg07
20

Step-by-step explanation:

\green{<strong><u>answEr</u></strong><strong><u>:</u></strong><strong><u>:</u></strong><strong><u>}</u></strong>

let the 2 digits be x and y...

using condition::

x+y = 9

the number is:

====>10x+y....

when we interchange,

====> 10y+x

____________________________

using condition 2,

(10y+x) - (10x+y) = 27

====> 10y-y + x - 10x=27

====> 9y-9x=27

====> 9(y-x)=27

====> y-x = 3

___________________________

we get 2 equation which are::

(1) x+y=9

(2) y-x = 3

\red{adding \:these\: equations,}

====>2y = 12

====> y = 6

\boxed{===&gt; x = 3}

thus,

the number was 36

___________________________

@jtg07

@RamSiyaKeLavKushUnit

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Answered by pulakmath007
0

Answer:

Let the digit in unit place be Y and the digit in tens place be X

Then the two digits number is 10X+Y

he two digits number is 10X+YBy the given condition

X+Y=9 ……...... (1)

(1)On interchanging the digits, the new number will be 10Y+X

Now by the given condition

10Y+X-(10X+Y)=27

=> 10Y+X-10X-Y=27

=> 9Y-9X=27

=> 9(Y-X)=27

So Y-X=3…….............. ..(2)

..(2)Adding (1) & (2) we get;

we get;X+Y+Y-X=9+3=12

2Y=12

Y=12/2=6

Y=12/2=6X+Y=9 gives

X+6=9

X=3

X=3The required number is

= 10X+Y

=10×3+6

=30+6

=36

Hence the number is 36

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