Question

1) Sum of the digits of a two digits number is 8. When we interchange the digits, it is found that the
resulting new number is greater than the original number by 28. What is the two digits number?

2) Separate 178 into two parts so that the first part is 8 less than twice the second part.

3) If the same number be added to the numbers 5,11,15 and 31, the resulting number are in proportion. Find the number.​

Answer 1

Answer:

Step-by-step explanation:

2)  

Let x and y be the parts.

x+y=178

x=178-y

Again

x=2y-8

178-y=2y-8

178+8=2y+y

186/3=y

y=62

x=178-62= 116

3)

Let x be added to all the numbers.

(5+x) / (11+x)= (15+x)/ (31+x)

(5+x)*(31+x)=(15+x)*(11+x)

x^2 + 36x + 155= x^2+ 26x + 165

36x-26x=165-155

10x=10

x=10/10

x=1

the required no is 1.