1. Sum of the four consecutive terms in an A.P. is 68 and the sum of their squares is 1336. Find these terms.
Hint: Choose the terms in the form a - 3d, a-d, a+d, a +3d.
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The sum of four consecutive terms of an A.P. is 20 and the sum of their squares is 120. Find those numbers. MEDIUM.
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Let the terms be a - 3d, a - d, a + d, a + 3d .Given, Sum = 20 a - 3d + a - d + a + d + a + 3d = 20 4a = 20 a = 5 Also given, sum of squares = 120 (a - ... More
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