Question

1.Sum of three consecutive integers is 48. Find integers?
2.Factorize x2 - 12x + 11

Answer 1

Answer:

1. THE INTEGERS ARE 15,16,17

2. x²-12x+11 = (x-1)(x-11)

Step-by-step explanation:

1.

 LET THE FIRST INTEGER BE x

 SO,

 SECOND INTEGER = (x+1)

    THIRD   INTEGER = (x+2)

  SO,

  A.T.Q.,

   x+(x+1)+(x+2) = 48

   3x+3 = 48

   3x = 45

    x = 15

   x+1 = 16

   x+2 = 17

  THEREFORE,

  THE INTEGERS ARE 15,16,17

2.

  x²-12x+11

  x² -11x-x+11

  x(x-11) -1(x-11)

  (x-1)(x-11)

  THEREFORE,

  x²-12x+11 = (x-1)(x-11)

I HOPE YOU UNDERSTOOD THE QUESTION!!!

                                !!!JAI SHREE KRISHNA!!!

Answer 2

Answer:

Neeche dekh lijiye

Step-by-step explanation:

1. Let the integers be n, n+1, and n+2.

∴ n + n + 1 + n + 2 = 48

or 3n + 3 = 48

or n + 1 = 16.

or n = 15,

∴ The numbers are, 15, 16 and 17..

2. $x^{2}$ - 12$x^{1}$ + 11,

Let $x^{2}$ - 12$x^{1}$ + 11 = 0

by middle term split,

$x^{2}$ - (11 + 1)$x^{1}$ + 11 = 0

$x^{2}$  - 11$x^{1}$ - $x^{1}$ + 11 = 0

$x^{1}$($x^{1}$ - 11) -1($x^{1}$ - 11) = 0

= ($x^{1}$ - 11)($x^{1}$ - 1) = 0

∴ $x$ = 11, and 1.