Question

1)Suppose a gas expands by 500 ml (0.500 L) against a pressure of 1.20 atm and no heat is exchanged with the surroundings during the expansion. (a) How much work is done in the expansion?​

Answer 1

Answer:

)Suppose a gas expands by 500 ml (0.500 L) against a pressure of 1.20 atm and no heat is exchanged with the surroundings during the expansion. (a) How much work is done in the expansion?

Answer 2

Given : Volume change, ∆V = 0.5 L, Pressure = 1.20 atm

To find : work done in the expansion

Solution : Given that no heat is exchanged with the surroundings during the expansion

• Therefore, enthalpy change, ∆E = 0

And the process is adiabatic

$W = nR(P1V1 - P2V2) / \gamma - 1$

• But in the above question, it is not mentioned that the gas in monoatomic, dia or poly.

• So we don't know the value of γ to calculate work done in the expansion.