Question

(1) suppose a high energy photon is scattered by an electron initially at rest. Assume the photon is back scattered and the engergy of electron the rest mass energy of electron (a) calculate the wave length shift (b) show that the energy of the back scattered photon is half of the rest mass energy of electron (c) calculate the electrons recoil kinetic energy,if the energy of the incident photon is 150MeV (hint : 1eV=1.6×10^-19 jould: and 1MeV =10^6eV)​

Answer 1

Explanation:

Rest mass of electron and positron =9.11×

${10}^{ - 31}$

kgs

Energy to electron =0.56MeV

$\frac{1}{2} \times 9.11 \times {10}^{ - 31} \times {v}^{2} = 0.56 \times 1.6 \times {10}^{ - 19} \times {10}^{6} joules$

hope it helps uhh mate