Question

1. Suppose an alpha particle accelerated
by a potential of V volt is allowed to
collide with a nucleus whose atomic
number is Z, then the distance of
closest approach of alpha particle to
the nucleus is
(a) 14.42 Å
V
(b) 14.4 - Å
Z
V
Z
(c) 1.44-Å
V
V
(d) 1.44 - Å
Z​

Answer 1

Answer:

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Explanation:

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