Question

1.
Suppose that g (x) = 1 + Vx and f[g(x)] = 3 + 2 VX + x, then f (x)
is
(a) 1 + x
(b) 2 + x
(c) 2+x?
(d) 1 + 2x2​

Answer 1

Answer:

Answer

g(x)=1+x

And f(g(x))=3+2x+x

then f(x)=?

f(g(x))=3+2x+x [ terms splitting]

f(g(x))=2+(1+2x+x)

Also, (1+x)2=1+x+2x

⇒f(g(x))=2+(1+x)2

⇒f(x)=2+x2

f(x)=x2+2

checking

fog=(1+x)2+2     [(a+b)2=a2+b2+2ab]

=1+x+2x+