1. Suppose the half-life of a certain radioactive substance is 20 days and there 10g initially.
substance remaining after 75 days.
are 10g initially. Determine the exponential model and the amount
C.
How much
Solution:
Answer:
Activity 1.2
Solution:
Danzel deposited an amount of P10,000.00 in a hank that nun
10
Answers
Given : half-life of a certain radioactive substance is 20 days and there 10g initially.
To Find : substance remaining after 75 days.
exponential model
Solution:
ln (Nt/N₀) = -kt
Nt = mass of radioactive material at time interval (t)
N₀ = mass of the original amount of radioactive material
k = decay constant
t = time interval (t1/2 for the half-life)
ln (Nt/N₀) = -kt
N₇₅ = ?
N₀ = 10 gram
N₂₀ = 5 gram
t = 20
ln(1/2) = -20k
-0.693 = -20k
=> k = 0.03465
ln (Nt/N₀) = -0.03465 t
ln (Nt/10) = -0.03465 (75)
ln (Nt/10) = -2.59875
Nt/10 = e^(-2.59875)
Nt/10 = 0.074366
=>Nt = 0.74366
substance remaining after 75 days. = 0.74366 g
Nt = N₀e^ (-0.03465 t ) is the exponential model
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Answer:
1. Suppose the half-life of a certain radioactive substance is 20 days and there 10g initially.
substance remaining after 75 days.
are 10g initially. Determine the exponential model and the amount
C.
How much
Solution:
Answer:
Activity 1.2
Solution:
Danzel deposited an amount of P10,000.00 in a hank that nun
10