Question

1 ते n नैसर्गिक सम संख्यांची बेरीज 462 आहे, तर n ची किंमत काढा.​

Answer 1

Step-by-step explanation:

Given If the sum of n natural even numbers is 462, then find the value of n.

• Let Sn be the sum of  numbers.
• So the first even natural numbers are 2,4,6,8,10…………n
• here a = 2, d = 2
• So we have Sn = n/2 (2a + (n – 1)d)
•                  462 = n/2 ( 2(2) + (n – 1) 2)
•                 462 = n/2 (4 + 2n – 2)
•                 462 = n/2 (2 + 2n)
•                             2n^2 + 2n – 924 = 0
•                        n^2 + n – 462 = 0
•                       n^2 + 22n – 21n – 462 = 0
•                        n(n + 22) – 21 (n + 22) = 0
•                         (n + 22) (n – 21) = 0
•                           n = - 22, 21
•    So the value of n is 21

Reference link will be

https://brainly.in/question/8464091#