Question

(1-tan 0)2+(1+tan 0)2 =2 sec2 0​

Answer 1

Answer:

Take left hand side of the equation

(1+tanA)² + (1−tanA)² = 2sec²A.

LHS = (1+tanA)² + +(1−tanA)² = 1 +

tan²A+ 2tan A + 1 +tan²A - 2tanA

=2+2tan²A

=2(1+tan²A )

=2sec²A

=RHS