Question

1+tan?
1+ cot'A
tan A
1-cot A
tan'a​

Answer 1

The proof of the given equality is as follows :

tanA1−cotA+cotA1−tanA=sinAcosA1−cosAsinA+cosAsinA1−sinAcosA  

=sin2AcosA(sinA−cosA)+cos2AsinA(cosA−sinA)

=sin3A−cos3AcosAsinA(sinA−cosA)

=sin2A+cosAsinA+cos2AcosAsinA

=1+cosAsinAcosAsinA

=1+secAcscA.

tan A/1-cot A + cot A/1-tan A = 1+sec A cosec A

Answer 2

Answer:

the answer will be LHS=RHS.