Math, asked by pk4771016, 4 months ago

1) tan 10° tan 15° tan 75° 80° = 1
2) sin 40° sec 50° + cos 40° cosec 50° = 2


HELP ME I WILL MARK YOU BRAIN LIST IF THIS TWO ANSWER IS CORRECT ​​

Answers

Answered by kbheemashankar23
2

Answer:

1) tan10° tan15° tan75° tan80°=1

LHS=tan10° tan15° tan75° tan80°

tan(90°-80°) tan(90°-75°) tan75° tan80°

cot80° cot75° tan75° tan80°

1/tan80° 1/tan75° tan75° tan80°

=1

LHS =RHS

2)sin40° sec50°+cos40° cosec50°=2

LHS = sin40° sec50°+cos40° cosec50°

=sin(90°-50°) sec50°+cos(90°-50°) cosec50°

=cos50° sec50°+sin50° cosec50°

=1+1

=2

LHS=RHS

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