(1+tan 15°) (1+tan30°) = ?
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Answer:
tan 15 = tan(45-30)
tan45- tan30/1+tan45*tan30
=1-1/√3/1+1*1/√3
√3-1/√3+1
So, (1+tan15)(1+tan30)
(1+√3-1/√3+1)(1+1/√3)
if we solve this we'll get the answer as 4-2√3
hope it helps.....
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