Question

(1) (tan 15°xtan 45°xtan 60°xtan 759)​

Answer 1

Answer:

Let put every ratio in such a manner that the sum of ratio will be 90°

tan15° tan75° tan30° tan60° tan45

tan(90-75) tan75° tan(90-60) tan60° tan45

* [tan(90-A)=cotA]

So

cot75°tan75° cot60°tan60°tan45°

1/tan75°*tan75° 1/tan60°*tan60° tan45

1*1*1 "[cotA=1/tanA] [tan45°=1]"

So the solution to this is

1