Question

(1+tan^2)(1-sin)(1+sin)=1

Answer 1

Ahoy,

(1+tan^2)(1-sin)(1+sin)

=> By identity 1+ tan^2 = sec^2

So,

$sec {}^{2} (1 {}^{2} - \sin {}^{2} )$

By identity :- 1^2-sin^2 = cos^2

=> sec^2 × cos^2

=> 1 = RHS

Cheers!

Answer 2

Hey !!!


Here is your answer

⬇️⬇️⬇️⬇️⬇️


⏩⏩we have to prove that


(1 + tan²θ)( 1 - sinθ)(1 + sinθ) = 1


L.H.S

(1 + tan²θ)( 1 - sinθ)(1 + sinθ)

(Sec²θ)( 1 - sin²θ)

(sec²θ)(Cos²θ)

1/Cos²θ × Cos²θ

1


$i \: hope \: it \: will \: help \: you$
Thank you ☺️✌️